Chain Rule: Chain Rule is differential rule to evaluate the inner functions of the given functions.
Example y= sin(cosx) , y= log ( tanx). Here cosx is the inner function of sin and tanx is the inner function of log
2. Find the derivative of x for y = log(sinx)=$\frac{\mathrm{d} log(sinx)}{\mathrm{d}}$ x $\frac{1}{sinx}$cosx = tanx.
Explanation: First write the derivative of log with inner term and then differentiate the inner function sinx.
3. Find the derivative of y = tan ( secx + cosx)
$\frac{\mathrm{d} tan(secx+cosx)}{\mathrm{d} x}$= $sec^{2}$(secx+cosx)$\times (secxtanx-sinx)
Explanation: First write the derivative of tan with inner term and then differentiate the inner function secx + cosx
For the above example given we can substitute the inner one as u . That is y= sinu so $\frac{\mathrm{d} y}{\mathrm{d} x}$= $\frac{\mathrm{d} y}{\mathrm{d} u}$$\times$$\frac{\mathrm{d} u}{\mathrm{d} x}$.
1. Find the derivative y=$cos(3x^{4}+8)^2$
Explanation:
Step1: Let $(3x^{4}+8)^2$ =u
So, y= $cosu^2$
we have the formulae $\frac{\mathrm{d} y}{\mathrm{d} x}$=$\frac{\mathrm{d} y}{\mathrm{d} u}$$\times$$\frac{\mathrm{d} u}{\mathrm{d} x}$.
$\frac{\mathrm{d} y}{\mathrm{d} x}$= $\frac{\mathrm{d} cosu}{\mathrm{d} u}$$\times$$\frac{\mathrm{d} (3x^{4}+8)^2 }{\mathrm{d} x}$
step2: sinu$\times$ $2(3x^4)$$\times$ $12x^3$.
Explanation: The derivative of cosu is sinu and the derivative of $u^2$ is 2u and the inner most term is
$x^4$ so the derivative is $4 x^3$.
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